15y^2-19y+4=

Solution for 15y^2-19y+4= equation:

Simplifying
15y2 + -19y + 4 = 0

Reorder the terms:
4 + -19y + 15y2 = 0

Solving
4 + -19y + 15y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + -15y)(1 + -1y) = 0

Subproblem 1
Set the factor '(4 + -15y)' equal to zero and attempt to solve:

Simplifying
4 + -15y = 0

Solving
4 + -15y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -15y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -15y = 0 + -4
-15y = 0 + -4

Combine like terms: 0 + -4 = -4
-15y = -4

Divide each side by '-15'.
y = 0.2666666667

Simplifying
y = 0.2666666667
Subproblem 2
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Solution
y = {0.2666666667, 1}